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A straight wire carring current I is turned into a circular loop. If the magnitude of magnetic moment associated with it in M.K.S. unit is M, the length of wire will beA. `4piiM`B. `sqrt((4piM)/i)`C. `sqrt((4pii)/M)`D. `(Mpi)/(4i)` |
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Answer» Correct Answer - B Megnetic moment of circular loop carrying current `M=IA=I(piR^(2))=Ipi(L/(2pi))^(2)=(IL^(2))/(4pi) implies L=sqrt((4piM)/I)` |
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