InterviewSolution
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InterviewSolution
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A straight wire carrying a current of `12A` is bent into a semicircular arc of radius `2*0cm` as shown in figure. Consider the magnetic field `vecB` at the centre of arc. (a) What is the magnetic field due to the staight segments? (b) In what way the contribution to `vecB` from the semicircle differs from that of a circular loop and in what way does it resemble? (c) Would your answer be different if the wire were bent into a semicircle arc of the same radius but in the opposite way as shown in figure |
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Answer» (a) `dl` and r for each element of the straight segments are parallel. Therefore, `dl xx r = 0`. Straight segments do not contribute to |B|. (b) For all segments of the semicircular arc, `dl x× r` are all parallel to each other (into the plane of the paper). All such contributions add up in magnitude. Hence direction of B for a semicircular arc is given by the right-hand rule and magnitude is half that of a circular loop. Thus B is `1.9 xx 10^(–4) T` normal to the plane of the paper going into it. (c) Same magnitude of B but opposite in direction to that in (b). |
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