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    				| 1. | A straight wire of mass 200 g and length 1.5 m carries a current of 2 A. It is suspended in mid-air by a uniform horizontal magnetic field B. What is the magnitude of the magnetic field? | 
| Answer» From Eq. (4.4), we find that there is an upward force F, of magnitude IlB,. For mid-air suspension, this must be balanced by the force due to gravity: `m g = I lB` `B = (mg)/(Il)` `=(0.2 xx 9.8)/(2 xx 1.5) = 0.65 T` Note that it would have been sufficient to specify `m//l`, the mass per unit length of the wire. The earth’s magnetic field is approximately `4 ×x 10^(–5) T` and we have ignored it. | |