A stream of glass beads, each with a mass of 15 gram, comes out of a horizontal tube at a rate of 100 per second. The beads fals a distance of 5m to a balance pan and bounce back to their original height. How much mass (in kg) must be placed in the other pan of the balance to keep in pointer at zero?

A stream of glass beads, each with a mass of 15 gram, comes out of a h

1.	A stream of glass beads, each with a mass of 15 gram, comes out of a horizontal tube at a rate of 100 per second. The beads fals a distance of 5m to a balance pan and bounce back to their original height. How much mass (in kg) must be placed in the other pan of the balance to keep in pointer at zero?
Answer» Solution :`/_\vecp` (change in MOMENTUM PER collision) `=2msqrt(2gh)=2xx15xx10^(-3)(10)=0.3kg ms^(-1)` Then i `/_\p_(100)` ( in 1 second) `=30kgms^(-1)` FORCE EXERTED `=30N` So weight requried `=30N`. So mass `=3kg`

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