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A string breaks under a load of 4.8kg A mass of 0.5 kg is attached to one end of a string 2 m long and is rotated in a horizontal circle. Calculate the greatest number of revolutions that the mass can make without breaking the string.

Answer» Here , ` T = 4.8 kg wt . =4.8 xx 9.8 N `
` m = 0. 5 , r = 2 m , v = ? `
As `T = m r omega^(2) = m r (2 pi v)^(2)`
`= 4 pi^(2) m r v^(2)`
`:. v^(2) = (T)/(4 pi^(2) mr )=(4.8 xx 9.8)/(4 xx 9.87 xx 0.5 xx 2)`
` = 1.215 `
`v^(2) = sqrt(1.215)=1.102 "rps"`
Greatest number of revolutions that the mass can make per minute
`= 1. 102 xx 60 = 66 . 12 "rpm"` .


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