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A string is wrapped on a wheel of moment of inertia 0.20 kg-m^2 and radius 10 cm and goes through a light pulley to support a block of mas 2.0 kg as shown in figure. Find the acceleration of the block. |
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Answer» Correct Answer - B `I=0.20kg-m^2` (bigger pulley) `r=10cm=0.1m, Smaller pulley is light `Mass of the block m=2kg` Therefore `mg-T=ma`……….1 `Txxr=Ixxalpha` `rarr T=(Ia)/r^2`………….2 `rarr mg=(m+I/r^2)a` [Using 2 and 1] `rarr a=(mg)/((m+I/r^2))` `=(2xx9.8)/{(2+(0.2/0.01)}` `=19.6/22=0.89m/s^2` therefore acceleration of the block `=0.89m/s^2` |
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