InterviewSolution
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InterviewSolution
| 1. |
A string of length 0.5 m carries a Bob with a period2π s. Calculate angle of inclination of string with vertical and tension in the string |
| Answer» <p>for equilibirium,</p><p>mω²r = mgcosA</p><p>where,ω is angular velocity , m is the mass of bob , r is the radius of circular motion and A is theangle of inclination of bob with vertical.</p><p>We know, ω = 2π/T , here T is time periodso, m{2π/T}²r = mgcosA⇒ T = 2π√{r/gcosA} now, put r = 0.5m , T = 2π secso, 2π = 2π√{0.5/10cosA}⇒1 = 1/20cosA⇒ cosA = 1/20so, A = cos⁻¹(1/20)</p><p>Hence, angle of inclination = cos⁻¹(1/20)</p> | |