A string of length '2a' has been tied at A and B such that AB='a'. The string is passing through a bead C and initially the bead is very close toA. Now the bead is allowed to fall. Let h be the height by which the bead falls when the string becomes taut and v be the speed of the bead just after the string becomes taut. Pick correct option (s):-

A string of length '2a' has been tied at A and B such that AB='a'. The

1.	A string of length '2a' has been tied at A and B such that AB='a'. The string is passing through a bead C and initially the bead is very close toA. Now the bead is allowed to fall. Let h be the height by which the bead falls when the string becomes taut and v be the speed of the bead just after the string becomes taut. Pick correct option (s):-
Answer» `V=SQRT(3ag)sin(26.5^(@))` `v=sqrt(1.5ag)sin(26.5^(@))` `h=(3a)/5` `h=(3a)/5` SOLUTION :`h=(3a)/4` `v_(0)=sqrt(2gh)` `v_(0)=sqrt(1.5ag)` and `v=v_(0)COS(90^(@)-26.5^(@))` `implies v_(0)sin(26.5^(@))` `implies v=sqrt(1.5ag) sin (26.5^(@))`

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