InterviewSolution
Saved Bookmarks
| 1. |
A string of length `L` is fixed at one end and carries a mass `M` at the other end. The string makes `2//pi` revolution per second around the vertical axis through the fixed end as shown in the figure, then tension in the string is. A. `ML`B. `2ML`C. `4ML`D. `16ML` |
|
Answer» Correct Answer - D `omega=2piN=2pi((2)/(pi))=4rad//s` As in the previous solution, `T=Momega^(2)L=16ML` |
|