1.

A string of length `L` is fixed at one end and carries a mass `M` at the other end. The string makes `2//pi` revolution per second around the vertical axis through the fixed end as shown in the figure, then tension in the string is. A. `ML`B. `2ML`C. `4ML`D. `16ML`

Answer» Correct Answer - D
`omega=2piN=2pi((2)/(pi))=4rad//s`
As in the previous solution, `T=Momega^(2)L=16ML`


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