1.

A string of lenth l fixed at one end carries a mass m at the other end. The strings makes `(2)/(pi)revs^(-1)` around the axis through the fixed end as shown in the figure, the tension in the string is A. 16 mlB. 4 mlC. 8 mlD. 2 ml

Answer» Correct Answer - A
Balancing horizontal forces,
`Tsintheta=mromega^(2)`
or `Tsintheta=m(l sintheta)omega^(2)`
`therefore" "T=mlomega^(2)=ml(2pif)^(2)`
`=ml(2pixx(2)/(pi))^(2)=16ml`


Discussion

No Comment Found

Related InterviewSolutions