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A string of lenth l fixed at one end carries a mass m at the other end. The strings makes `(2)/(pi)revs^(-1)` around the axis through the fixed end as shown in the figure, the tension in the string is A. 16 mlB. 4 mlC. 8 mlD. 2 ml |
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Answer» Correct Answer - A Balancing horizontal forces, `Tsintheta=mromega^(2)` or `Tsintheta=m(l sintheta)omega^(2)` `therefore" "T=mlomega^(2)=ml(2pif)^(2)` `=ml(2pixx(2)/(pi))^(2)=16ml` |
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