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A string of mass 2.50 kg is under a tension of 200 N. The length of the stretched string is 20.0 m. If the transverse jerk is struck at one end of the string, how long does the disturbance take to reach the other end? |
Answer» Tension in the string. T = 200; Mass of string, M = 2.50 g; Length l = 20 m Mass per unit length, m = M/L = 2.5/20 = 0.125 kg m-1 Velocity, v = √{T/m} = √{200/0.125} = 40 ms-1 time taken by the disturbance to reach other end, t = l/v = 20/40 = 0.5 s. |
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