1.

A string when stretched with a weight of 9 kg weigth produces a note of frequency 256. Calculate the weight to produces an octave of the note.

Answer»

36 kg wt
9/4 kg wt
18 kg wt
4 kg wt.

Solution :For stretched string v = `(1)/(2l ) sqrt((T)/(m)) rArr v prop sqrt(T)` .
one OCTANE higher means to double the frequency.
`THEREFORE (v_(2))/(v_(1)) = sqrt((T_(2))/(T_(1))) "" rArr "" (2 xx 256)/(256) = sqrt((T)/(9 "kg wt"))`
`therefore T_(2) = 36 ` kg wt.
Hence correct choice is (a).


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