A strip of nickel metal is placed in a 1molar solution of Ni(NO_3)_2 and a strip of silver metal is placed in a one molar solution of AgNO_3. An electrochemical cell is created when the two solution are connected by a salt bridge and the two strips are connected by wires to a voltmeter. (a) Write the balanced equation for the overall reaction occuring in the cell and calculate the cell potential. (b) Calculate the cell potential, E at 25^@C for the cell, if the initial concentration of Ni(NO_3)_2 is 0.100 molar and the initial concentration of AgNO_3 is 1.00 molar. [E_(Ni^(2+)//Ni)^@=-0.25V, E_(Ag^+//Ag)^@=0.80 VJ] log10^-1=-1

A strip of nickel metal is placed in a 1molar solution of Ni(NO_3)_2 a

1.	A strip of nickel metal is placed in a 1molar solution of Ni(NO_3)_2 and a strip of silver metal is placed in a one molar solution of AgNO_3. An electrochemical cell is created when the two solution are connected by a salt bridge and the two strips are connected by wires to a voltmeter. (a) Write the balanced equation for the overall reaction occuring in the cell and calculate the cell potential. (b) Calculate the cell potential, E at 25^@C for the cell, if the initial concentration of Ni(NO_3)_2 is 0.100 molar and the initial concentration of AgNO_3 is 1.00 molar. [E_(Ni^(2+)//Ni)^@=-0.25V, E_(Ag^+//Ag)^@=0.80 VJ] log10^-1=-1
Answer» SOLUTION :(i) `Ni(s)to Ni^(2+) (aq) +2e^-` `2Ag^+ (aq)+2e^(- ) to 2Ag (s) ` `Ni(s)+2Ag^+ (aq)to Ni^(2+) (aq)+2Ag(s)` `E_(cell)^@=E_(cathode)^@-E_(anode)^@` `=0.80-(-0.25)=1.05 V` (II) `E_(cell)=E_(cell)^@-0.0591/2log""([Ni^(2+)])/([Ag^+]^2)` `=E_(cell)^@-0.0591/2log""0.1/(1)^2` `=0.05 -0.0591/2 times (-1)` `=1.05 +0.0295=1.0795 V`