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A student had taken solutions of KI, H_(2)S, C_(2)H_(5)OH and NaBr in four separate test tube but he forgot to label them. By taking a mall sample of the solution from each of the four test tubes, suggest a method by which he can find out the solution in each test tube by using the same reagent in each of the test tubes. Give the reaction in each case. |
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Answer» Solution :The solution present in each of the four test tubes can be found by adding a mixture of potassium dichromate crystals and concentrated `H_(2)SO_(4)` . A different observation will be noted in different CASES (i) In testcontaining KI, violet vapours of `I_(2)` will appear `K_(2)Cr_(2)O_(7) + 7H_(2)SO_(4) + 6KI rarr 4K_(2)SO_(4) + Cr_(2)(SO_(4))_(3) + underset("violet vapours)")(3I_(2))+7H_(2)O` (ii) In test tube containing `H_(2)S` solution , yellow ppt. of sulphur will appear `K_(2)Cr_(2)O_(7) + 4H_(2)SO_(4) + 3H_(2)S rarr K_(2)SO_(4) +Cr_(2)(SO_(4))_(3)+ 7H_(2)O + underset ("(yellow)")(3S)` (iii) In test tube containing `C_(2)H_(5)OH`, vinegar smell will be noticed due to formation of acetic acid `K_(2)Cr_(2)O_(7) + 4H_(2)SO_(4) rarr K_(2)SO_(4)+Cr_(2)(SO_(4))_(3)+3(O)` `CH_(3)CH_(2)OH+ (O) rarr CH_(3)CHO+ H_(2)O` `CH_(3)CHO+ (O)rarr CH_(3)COOH` (iv) In test tube containing NABR, the colour of the solution will turn BROWN due to formation of `Br_(2)` which dissolves in the solution . Reaction is similarto reaction given in (i) above. |
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