1.

A student is standing at a distance of 50 metre from the bus. As soon as the bus begins its motion with an acceleration of 1m//s^(2), the student starts running towards the bus with a uniform velocity u. assuming the motion to be along a straight road, the minimum value of u. so that the student is able to catch the bus is

Answer»

`12 m//s^(-1)`
`10 m//s^(-1)`
`8 m//s^(-1)`
`5 m//s^(-1)`

Solution :Applying `V^(2)-u^(2)=2`as, for the motion of bus
`u=0, a=1 ms^(-2)`
`v^(2)-0=2xx1xx50=100`
`:. V=10 ms^(-1)`
Hence to catch the bus the student should RUN at least with uniform VELOCITY of `10 ms^(-1)`


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