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A student measued the diameter of a small steel ball using a screw gauge of least count `1.001 cm`. The main scale reading is `5 mm` and zero of circular scale division coincides with 25 divisions above the reference level. If screw gauge has a zero erroof `-0.004 cm`, the correct diameter of the ball isA. 0.053 cmB. 0.525 cmC. 0.521 cmD. 0.529 cm |
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Answer» Correct Answer - D Diameter of the ball =MSR + CSR`xx` (Least count)-zero error `=0.5 cm+25xx0.001-(-0.004)` `=0.5 + 0.025 +0.004` `=0.529 cm` |
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