1.

A student measured the length of a rod wrote it as 3.50 cm. Which instrument did he use to measure it ?

Answer»

A screw gauge having `50` divisions in the circular SCALE and pitch as `1` mm.
A METER scale.
A vernier CALLIPER where the `10` divisions in vernier scale matches with `9` division in main scale and main scale has `10` divisions in `1` cm.
A screw gauge having `100` divisions in the circular scale and pitch as `1` mm.

Solution :Here he is to measure `3.50cm`, which is best measured by vernier calliper because the least count of vernier calliper is `(1)/(10)mm=0.1mm=0.01cm`.
Hence `(c )` is the correct choice.


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