1.

A substance C_(4)H_(10)O yields on oxidation a compound C_(4)H_(8)O which gives an oxime and a positive iodoform test. The original substance on treatment with conc. H_(2)SO_(4) gives C_(4)H_(8) . The structure of the compound is

Answer»

`CH_(3)CH_(2)CH_(2)CH_(2)OH`
`CH_(3)Ch(OH)CH_(2)CH_(3)`
`(CH_(3))_(3)COH`
`CH_(3)CH_(2)-O-CH_(2)CH_(3)`

Solution :`CH_(3)CH(OH)CH_(2)CH_(3)OVERSET("CONC." H_(2)SO_(4))to underset((C_(4)H_(8)))(CH_(3)CH=CHCH_(3) `
`underset(2-"BUTANOL")(CH_(3)CHOHCH_(2)CH_(3))overset([O])to underset("Butanol")(CH_(3)COCH_(2)CH_(3))`
Butanone gives both an oxime and positive iodoform test, therefore, the original compound is 2-butanol.


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