1.

A substance reacts according to the according to the first roder rate law and the specific reaction rate for the reaction is 1xx10^(-2) s^(-1). If the initial concentration is 1.0 M. (a) What is the initial rate ? (b) What is the reaction rate after 1 minutes ?

Answer»

Solution :(a) Initial rate of a first ORDER reaction
=KC
`=1xx10^(-2)xx1.0`
`=1xx10^(-2)" MOL L"^(-1)s^(-1)`
(B) Concentration after 60 second is calculated by applying the first order kinetic equation ,
`k(2.303)/60log_101/(1-x)`
or `1xx10^(-2)=(2.030)/60[-log(1-x)]`
or `(60xx10^(-2))/(2.303)=-log(1-x)=0.2605`
`log(1-x)=-0.2605=1.73395`
`(1-x) = antilog of (1.7395)`
`=0.5489" mol L"^(-1)`


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