A sugar syrup of weight 214.2 g contains 34.2 g of sugar (C_(12)H_(22) – InterviewSolution

1.	A sugar syrup of weight 214.2 g contains 34.2 g of sugar (C_(12)H_(22)O_(11)). Calculate (i) molal concentration (ii) mole fraction of sugar in the syrup.
Answer» Solution :`"Solute "(C_(12)H_(22)O_(11))=34.2g,"Solution = 214.2 G,Solvent = " 214.2-34.2=180 g = 0.180 KG.` `"Molal conc. "=(34.2//342mol)/(0.180kg)="0.556 mol kg"^(-1),"Mole FRACTION "=(34.2//342)/(180//18+34.2//342)=0.0099`

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