1.

A sum of money amounts to ₹ 10240 in 2 years at 6 2/3% per annum, compounded annually. Find the sum. ​

Answer»

Given:-

  • \sf{A = Rs.10240}
  • \sf{T = 2\:years}
  • \sf{R = 6\dfrac{2}{3}\% = \dfrac{20}{3}\%}

To FIND:-

SUM of money

Solution:-

We know,

\sf{A = P\bigg(1 + \dfrac{r}{100}\bigg)^t}

= \sf{10240 = P\bigg(1 + \dfrac{20}{\dfrac{3}{100}}\bigg)^2}

= \sf{10240 = P\bigg(\dfrac{100 + \dfrac{20}{3}}{100}\bigg)^2}

= \sf{10240 = P\bigg(\dfrac{300+ 20}{3}\times\dfrac{1}{100}\bigg)^2}

= \sf{10240 = P\bigg(\dfrac{320}{3}\times\dfrac{1}{100}\bigg)^2}

= \sf{10240 = P\bigg(\dfrac{320}{300}\bigg)^2}

= \sf{P = 10240\times \dfrac{300}{320}\times\dfrac{300}{320}}

= \sf{P = 9000}

\sf{\therefore The\:Sum\:of\:money\:is\:Rs.9000}

From the solution:-

  • A = Amount
  • P = Principal
  • T = Time
  • R = RATE


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