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a sum of money become rs. 6500 after 3 years and 10562.50 after 6 years on compund interst. the sum is |
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Answer» Let the SUM of Money be ′ P ′ . A=P(1+ 100 R ) T where R= Rate of Interest. AMOUNT after 3 years =6500 ⇒6500=P(1+ 100 R ) 3 ⟶(I) Amount after 6 years =10,562.5 ⇒10562.5=P(1+ 100 R ) 6 ⟶(II) From eq(I) P 6500 =(1+ 100 R ) 3 ⇒( P 6500 ) 2 =(1+ 100 R ) 6 ⟶(III) Putting eq(III) in eq(II) 10562.5=P( P 6500 ) 2 ⇒10562.5=P× P 2 (6500) 2⇒P= 10562.5 (6500) 2 =4000 Hence, the sum of 4000. |
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