1.

A sum reckoned at 20% per annum amount to ₹ 40983 in 10 years 31 days.find the sum

Answer»

ANSWER:

  • The sum = ₹ 13,588.5

GIVEN:

  • A = ₹ 40983

  • N = 10.08 years

  • R = 20%

TO FIND:

  • The sum

FORMULA:

  • A = P + S.I

  • S.I = pnr / 100

EXPLANATION:

40983 = \dfrac{p \times 10.08 \times 20}{100} + p \\ \\ \\ 40983 = \dfrac{p \times 10.08 \times 2}{10} + p \\ \\ \\40983 = \dfrac{20.16p}{10} + p \\ \\ \\40983 = \dfrac{20.16p+ 10p}{10} \\ \\ \\ 409830 = 30.16p \\ \\ \\ p =\dfrac{409830}{30.16}\\ \\ \\p = Rs. 13,588.5

HENCE THE SUM WILL BE ₹ 13,588.5.

SOME MORE FORMULAE:

  • Simple interest - A = P( 1 + rt)

where A = Future interest , P = principal , r = RATE of interest

  • Continuly compounded intetest A = Peⁿ

Where A = Future interest , P = principal , r = rate of interest, n = time


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