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A surface is hit elastically and normally by n balls per second, each of mass m moving with velocity u. if each ball is made to hit the same surface with velocity 2 u, the force on the surface would become K times. What is the value of K ? |
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Answer» Correct Answer - 2 Here, initial force, `F_(1)` = rate of change of linear momentum of balls `=nxxm(-u-u) = -2nm u` Now force, `F_(2) = n xxm(-2 u - 2 u)` `=-4 nm u = 2 F_(1)` `:. K=2`. |
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