A swimmer coming out from a pool is covered with a film of water weigh

1.	A swimmer coming out from a pool is covered with a film of water weighing about 80 g. How much heat must be supplied to evaporate this water. If latent heat of evaporation for H2O is 40.79 kJ mol-1 at 100°C.
Answer» Amount of water present on the body of swimmer = 80 g = 80/18 mole Thus heat required to evaporate 80/18 mole H2O = 40.79 x 80/18 = 181.2 kJ

A swimmer coming out from a pool is covered with a film of water weighing about 80 g. How much heat must be supplied to evaporate this water. If latent heat of evaporation for H2O is 40.79 kJ mol-1 at 100°C.

Answer»

Amount of water present on the body of swimmer = 80 g = 80/18 mole

Thus heat required to evaporate 80/18 mole H2O = 40.79 x 80/18

= 181.2 kJ

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A swimmer coming out from a pool is covered with a film of water weighing about 80 g. How much heat must be supplied to evaporate this water. If latent heat of evaporation for H2O is 40.79 kJ mol-1 at 100°C.

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