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A syringe of diameter 1 cm having a nozzle ofdiameter 1 mm, is placed horizontally at a height 5 m from the ground as shown below. An incompressible non-viscous liquid is filled in the syringe and the liquid is compressed by moving the piston at a speed of 0.5 m s^(-1), the horizontal distance travelled by the liquid jet is(g=10 m s^(-2)) |
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Answer» 12.5 m  Here, Diameter of syringe, `d_1`=1 cm=`10^(-2)` m diameter of nozzle , `d_2`=1 mm = `10^(-3)` m According to equation of continuity , `A_1v_1=A_2v_2` `pi(d_1/2)^2 v_1=pi(d_2/2)^2 v_2` `pi((10^(-2)m)/2)^2 (0.5 m s^(-1))=pi((10^(-3)m)/2)^2 v_2` `v_2=((10^(-4) m^2)/(10^(-6) m^2))(0.5 m s^(-1))=50 m s^(-1)` `THEREFORE` Horizontal distance travelled by the liquid jet is `R=v_2sqrt((2H)/g) = (50 m s^(-1))sqrt((2(5m))/(10 m s^(-2))`=50 m |
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