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A system absorbs 100 cal of heat and does an external work of 150 J. if J=4.2 J/cal the change in internal energy isA. 420 JB. 270 JC. 250 JD. 150 J |
Answer» Correct Answer - B `DeltaQ=100xx4.2` `=420J` `DeltaW=150J` `DeltaU=DeltaQ-DeltaW` `=420-150=270J`. |
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