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A system has two charges q_A = 2.5 xx 10^(-7)C and q_(B)= - 2.5 xx 10^(-7)C located at points A:(0, 0, -15 cm) and B : (0, 0, + 15 cm), respectively. What are the total charge and electric dipole moment of the system ? |
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Answer» SOLUTION :Total charge of given SYSTEM. `q_(A) + q_(B) = -2.5 XX 10^(-7) + 2.5 xx 10^(-7) =0` Electric dipole moment of given dipole, `vecp = (2veca)Q ={vecr_(+) - vecr_(-)}.q` `=(vecr_(A) - vecr_(B))q` `=(0,0, -0.15) - (0,0,0.15) (2.5 xx 10^(-7))` `therefore vecp = (0,0, -0.3) (2.5 xx 10^(-7))` `therefore p = 7.5 xx 10^(-8) Cm` (Along -Z axis) |
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