1.

A system is provided `50xx10^(3)J` energy and work done on the system is `100J.` The change in internal energy is `:`A. `50kJ`B. `50.1kJ`C. `150J`D. `50J`

Answer» Correct Answer - B
`q=DeltaU+(-W)`
or `DeltaU=q+W`
Here `W` is work done on the system
`=50xx10^(3)+100=50100J`
`=50.1kJ`


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