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A system of binary stars of mass `m_(A)` and `m_(B)` are moving in circular orbits of radii `r_(A)` and `r_(B)` respectively. If `T_(A)` and `T_(B)` are at the time periods of masses `m_(A)` and `m_(B)` respectively thenA. `T_(A)gt T_(B)(if r_(A) gt r_(B))`B. `T_(A)gt T_(B) (if m_(A)gt m_(B))`C. `((T_(A))/(T_(B)))^(2) = ((r_(A))/(r_(B)))^(3)`D. `T_(A)=T_(B)` |
Answer» Correct Answer - D In binary star system angular velocity are qual hence the time period of both the stars are equal. `omega = (2pi)/(T_(A)) = (2pi)/(T_(B))` `therefore T_(A) = T_(B)` |
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