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A system of binary stars of mass `m_(A)` and `m_(B)` are moving in circular orbits of radii `r_(A)` and `r_(B)` respectively. If `T_(A)` and `T_(B)` are at the time periods of masses `m_(A)` and `m_(B)` respectively thenA. `T_(A)gtT_(B)(if r_(A)gtr_(B))`B. `T_(A)gtT_(B)(if m_(A)gtm_(B))`C. `((T_(A))/(T_(B)))^(2)=((r_(A))/r_(B))^(3)`D. `T_(A)=T_(B)` |
Answer» Correct Answer - `D` In binary star system angular velocity are equal hence the time period of both the stars are equal. `omega=(2pi)/(T_(A))=(2pi)/(T_(B))` `:. T_(A)=T_(B)` |
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