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A system undergoes a cyclic process in which it absorbs `Q_(1)` heat and gives out `Q_(2)` heat. The efficiency of the process is `eta` and work done is `W.` Select correct statement:A. `W = Q_(1) - Q_(2)`B. `eta =(W)/(Q_(1))`C. `eta = (Q_(2))/(Q_(1))`D. `eta =1 -(Q_(2))/(Q_(1))` |
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Answer» Correct Answer - A::B::D `eta = (0//P)/(1//P) = (W)/(Q_(1)) = (Q_(1)-Q_(2))/(Q_(1)) eta = 1 -(Q_(2))/(Q_(1))`. |
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