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Two containers of equal volume enclose equal masses of hydrogen and helium at `300K`. Find (i) the ratio of pressure and (ii) the ratio of total `K.E.` of all the molecules of the two gases. |
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Answer» Correct Answer - `P_(H_(2)) = 2P_(He), (kE_(H_(2)))/(kE_(He)) = (10)/(3)` `V_(H2) = V_(He)` `m_(H2) = m_(He), T = 300 K` (i) `P_(H2) V_(H2) = n_(H2) RT ………(i)` `P_(He). V_(He) = n_(He) = RT ……..(ii)` `(P_(H_(2)))/(P_(He)) = ((m_(H_(2))//2))/(m_(He)//4)` `rArr P_(H2) = 2P_(He)` (ii) `K.E. = (f)/(2)nRT` `(KE_(H_(2)))/(KE_(He)) =(f_(H_(2).n_(H_(2))))/(f_(He).n_(He)) =(5((m_(H_(2)))/(2)))/(3((m_(He))/(4))) =(10)/(3)` |
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