Saved Bookmarks
| 1. |
A tank with a smallcircular holecontains oil on top ofwater . It is immersed in a larger tankof the same oil . Water flows through the hole . (a) Whatis the velocityof this flowintially ? (b) Whenthe flows stops , what would be the position of the oil - water interface in the tank ? (density of oil = 8 gm/cc) |
|
Answer» Solution :ApplyingBernoulli.s equation between points 1 and 2 ` rArr P_(atm) +eho_(0)gh_(0) + rho_(w)gh_(w) = P_(atm) +rho_(0)G(h_(0)+h_(w))+1/2 rho_(w) V^(2)` `rArr 1/2 rho_(w)v^(2) = gh_(w) (rho_(w) - rho_(0))` ` rArr v = sqrt(2gh_(w)(1- (rho_(0))/(rho_(w)))) = sqrt(2 xx 9.8 xx 10/100 (1- (800)/1000))` ` = 0.63 ` m/s (b) In the termsof the heighth of oil water interface ` P_(atm) +rho_(0)g xx 5 + rho_(w)gh = P_(atm) +rho_(0)g (10+5) +1/2 rho_(w) v^(2)` ` rArr 1/2 rho_(w)v^(2) = g (rho_(w)H - rho_(n).10)` FLOW stops when `rho _(w)h - rho_(o) xx 10 ` ` :.h = 0.8 xx10 = 8 cm ` ` :. ` The interface is at a height 8 cm abovethe base . 
|
|