A taxi leaves the station X for station Y every 10 minutes. Simultaneously, a taxi leaves the station Y alsofor station X every 10 minutes. The taxis move at the same constant speed and go from X to Y or vice-versain 2 hours. How many taxis coming from the other side will each taxi meet enroute from Y to X?35/(1) 10(3) 12(2) 11(4) 23

A taxi leaves the station X for station Y every 10 minutes. Simultaneo

1.	A taxi leaves the station X for station Y every 10 minutes. Simultaneously, a taxi leaves the station Y alsofor station X every 10 minutes. The taxis move at the same constant speed and go from X to Y or vice-versain 2 hours. How many taxis coming from the other side will each taxi meet enroute from Y to X?35/(1) 10(3) 12(2) 11(4) 23
Answer» <p>When the taxi is just about to leave there will be taxis coming from the opposite side;</p><p>Our taxi will surely meet those taxis.</p><p> So, no. of taxis which will be in the path are:[(total time each taxi takes to reach destination)/(total time after which each taxi leaves the station)] + 1</p><p>In this case it is:120/10 + 1= 12+1=13(+1 as we need to take both the last and the first taxi).</p><p>So, we have total of 13 taxis on the path out of which we will subtract 1 as we are not considering the taxi meeting station Y.</p><p>Now, we need to calculate the no. of taxis which leave after our taxi leaves;</p><p>Those will be again:[(total time each taxi takes to reach destination)/(total time after which each taxi leaves the station)] +1in our case it is120/10 + 1= 12+1=13(+1 as we need to take both the last and the first taxi).</p><p>Now, we will subtract 2 as we have counted the taxi which will leave station X when our taxi leaves station Y twice and also as we are not considering the taxi meeting station X.</p><p>So, now we have a total of 12+11=23 taxis coming from other side which each taxi will meet enroute from Y to X</p>