1.

A telegraph wire of length 2500m, is kept in E-W direction, at a height of 10 m from the ground. If it falls freely on the ground, then what is the current induced in the wire? [Given: resistance of the wire = 25sqrt2Omega, g= 10ml/s^2 and B_H = 2xx10^-5T]

Answer»

SOLUTION :`E = B_mulv = B_mulsqrt2gh`
The velocity V is GIVEN by `V^2 = 2gh`
We get, `e = 50sqrt2xx10^-2V`
`therefore i = e/R = (50xx1.414xx10^-2)/35= 0.02A`


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