1.

A telescope has a magnification equal to 5 and the length of its tube is 60 cm. The focal length of its eye piece is

Answer»

10 cm
20 cm
30 cm
40 cm

Solution :Magnification of TELESCOPE
`m=(f_0)/(f_e)`
`THEREFORE 5=(f_0)/(f_e)`
`therefore f_0=5f_e`
Now tube length
`f_0+f_e`
`60=5f_e+f_e`
`therefore 60 =6f_e`
`thereforef_e=10` cm


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