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A telescope has a magnification equal to 5 and the length of its tube is 60 cm. The focal length of its eye piece is |
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Answer» 10 cm `m=(f_0)/(f_e)` `THEREFORE 5=(f_0)/(f_e)` `therefore f_0=5f_e` Now tube length `f_0+f_e` `60=5f_e+f_e` `therefore 60 =6f_e` `thereforef_e=10` cm |
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