1.

A tent is in the form of a cylinder of diameter 15 and height 2.4m surmounted by a cone of equal base and height 4m . find the capacity of tent and the cost of the canvas at 50 rs

Answer»

Answer:

Diameter of cylinder=15m

∴Radius of cylinder=

2

15

=7.5m

Height h

1

=2.4m

Height of CONE, h

2

=4m

Capacity of cone=πr

2

h

1

+

3

1

πr

2

h

2

=πr

2

(h

1

+

3

h

2

)

=

7

22

×(7.5)

2

(2.4+

3

4

)

=

7

4620

=660M

2

Slant height of cone=

r

2

+h

2

2

=

(7.5)

2

+(4)

2

=8.5m

CSA of cone=πrl=

7

22

×7.5×8.5

=200.35m

2

CSA of cylindrical part=2πrh=2×

7

22

×7.5×2.4

=113.14m

2

Total CSA of tent=200.35+113.14=313.49m

2

Therefore cost of canvas=313.49×50=Rs. 15674.5


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