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(A): The distance of closest approch to a gold nucleus of an alpha -particle of K.E 5.5Mev is about 4.0 xx 10^(-14)m (R): Rutherford by assuming that the coulomb repulsive force was only responsible for scattering. |
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Answer» Both .A. and .R. are true and .R. is the correct explanation of .A. |
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