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(a) The L.C.M and H.C.F of two polynomials p(x) and g(x) are 24-1) and (x + 1)(x2 + 1) respectively. If p(x) = x3 + x2 + x + 1, find q(x) |
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Answer» given :-LCM is 24-1 = 23HCF is (x+1)(X2+1) = x3 + x + x2 + 1 p(x) = x3 + x2 + x + 1TO find :-Q(x)= ?p(x) × q(x) = LCM × HCFx3 + x2 + x + 1 × q(x) = 23 × ( x3 + x2 + x + 1)q(x) = 23 × ( x3 + x2 + x + 1) / ( x3 + x2 + x + 1)q(x) = 23 |
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