1.

(a) The molar conductivities at infinite dilution of potassium chloride, hydrochloric acid and potassium acetate are 130.1, 379.4 and 95.6 S cm^(2)mol^(-1) respectively. Calculate the value of molar conductivity at infinite dilution for acetic acid. (b) If the molar conductivity of given acetic acid solution is 48.5 S cm^(2)mol^(-1) at 25^(@)C, calculate the degree of dissociation of acetic for acetic acid.

Answer»


Solution :`wedge^(@)(CH_(3)COOH)=wedge^(@)(CH_(3)COOK)+wedge^(@)(HCl)-wedge^(@)(KCl)=95.6+379.4-130.1=344.9" S "CM^(2)MOL^(-1)`
`alpha=(wedge_(m)^(@))/(wedge_(m)^(@))=(48.5)/(344.5)=0.141`


Discussion

No Comment Found