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(a) The number of nuclei of a given radioactive nucleus, at times t=0 and t=T, are N_0 and (N_(0)//n) respectively. Obtain an expression for the half life (T_(1//2)) of this nucleus in terms of n and T. (b) Identify the nature of the 'radioactive radiations', emitted in each step of the 'decay chain' given below: ""_(Z)^(A) X to ""_(Z-2)^(A-4) Y to ""_(Z-2)^(A-4) Yto""_(Z-1)^(A-4)W |
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Answer» Solution :(a) According to the ( exponential) law of radioactive decay `N=N_(0)e^(-lambda t)` Given, `N=N_(0) //n and t=T` `therefore ((N_0)/(n)) = N_(0) e^(- lambda t)` or `n=e^(lambda t)` `therefore lambda = (1 n (n))/( T)` `therefore` Half life `T_(1//2) (0.693)/( lambda) = (0.693 T)/( 1 n (n))` (b) (i) `alpha`-RAYS (ii) `GAMMA`-rays (iii) `beta`- rays. |
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