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(a) The resistance of 1/10 M solution is found to be 2.5 xx 10^(3) ohms. Calculate molar conductance (Given Cell constant = 1.15 cm). (b) Mention two general methods for prevention of corrosion. |
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Answer» Solution : (a) `k=1/Axx1/R=1.15xx1/(25xx10^(3))=4.60xx10^(-4)`ohm cm ` wedge_(m)=(1000xxk)/M=(1000xx4.60xx10^(-4))/0.1=4.60 ohm^(-1) cm^(2) mol^(-1)` (i) painting(ii) Electrochemical METHOD |
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