1.

A thermally insulated vessel contains an ideal gas of molecular mass M and ratio of specific heats gamma. It is moving with speed v and it is suddenly brought to rest. Assuming no heat is lost to the surroundings, its temperature increases by:

Answer»

`((gamma-1))/(2 gamma R)Mv^(2)K`
`(gamma Mv^(2))/(2R)K`
`((gamma-1))/(2R)Mv^(2)K`
`((gamma-1))/(2(gamma+1)R)Mv^(2)K`

SOLUTION :Work DONE is zero
So, LOSS in kinetic energy = CHANGE in internal energy of gas
`(1)/(2) mv^(2)=nC_(v)Delta T=n(R )/(gamma-1)Delta T`
`(1)/(2) mv^(2) =(m)/(M)(R )/(gamma-1)Delta T`
`therefore Delta T =(Mv^(2) (gamma-1))/(2R) K`
Correct choice : (c ).


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