A thermally isolated vessel contains `100g` of water at `0^(@)C`. When air above the water is pumped out, some of the water freezes and some evaporates at `0^(@)C` itself. Calculate the mass of the ice formed such that no water is left in the vessel. Latent heat of vaporization of water at `0^(@)C=2.10xx10^(6)J//kg` and latent heat of fusion of ice `=3.36xx10^(5)J//kg`.

A thermally isolated vessel contains `100g` of water at `0^(@)C`. When

1.	A thermally isolated vessel contains `100g` of water at `0^(@)C`. When air above the water is pumped out, some of the water freezes and some evaporates at `0^(@)C` itself. Calculate the mass of the ice formed such that no water is left in the vessel. Latent heat of vaporization of water at `0^(@)C=2.10xx10^(6)J//kg` and latent heat of fusion of ice `=3.36xx10^(5)J//kg`.
Answer» Total mass of the water `=M=100g` Latent heat of vaporization of water at `0^(@)C` `=L_(1)=21.0xx10^(5)J//Kg` & Latent heat of fusion of ice `=L_(2)=3.36xx10^(5)J//kg` Suppose, the mass of the ice formed `=m` Then, the mass of water evaporated `=M-m` Heat lost by the water in freezing`=` Heat taken by water in evaporation. Thus, `mL_(2)=(M-m)L_(1) or m-86 g`

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