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A thermocouple of negligible resistance produces an emf fo `40 mu V//^(@)C` in the linear range of temperature. A galvanometer of resistance `10 Omega` whose sensitivity is `1 mu A//div` is employed with the thermocouple. The smallest value of temperature difference that can be detected by the system willA. `0.25^(@)C`B. `0.5^(@)C`C. `1^(@)C`D. `0.1^(@)C` |
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Answer» Correct Answer - A For minimum deflection of 1 division required current `=muA` `implies " voltage required "=IR=(1muA)(10)=10muV` `therefore40muV-=1^@C` `implies10muV-=1/4""^(@)C=0.25^@C` |
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