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A thermodynamic system is taken through the cyclic `PQRSP` process. The net work done by the system is A. `20 J`B. `- 20 J`C. `400 J`D. `- 374 J` |
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Answer» Correct Answer - B b. Work done by the system = area of shade protion on `P - V` diagram. `= (300 - 100) 10^(-6) xx (200 - 100) xx 10^(3) = 20 J` And direction of process is anticlock wise so work done will be negative, i.e., `Delta W = - 20 J`. |
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