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A thermodynamic system undergoes cyclic process `ABCDA` as shown in figure. The work done by the system is A. `P_(0)V_(0)`B. `2P_(0)V_(0)`C. `(P_(0)V_(0))/(2)`D. zero |
Answer» Correct Answer - D `W_(OBC) = W_(ODA)` `therefore` Net work done `W_(OBC) - W_(ODC) = 0` |
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