1.

A thermodynamic system undergoes cyclic process `ABCDA` as shown in figure. The work done by the system is A. `P_(0)V_(0)`B. `2P_(0)V_(0)`C. `(P_(0)V_(0))/(2)`D. zero

Answer» Correct Answer - D
`W_(OBC) = W_(ODA)`
`therefore` Net work done
`W_(OBC) - W_(ODC) = 0`


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