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A thermodynamic system undergoes cyclic process `ABCDA` as shown in figure. The work done by the system is |
Answer» `W_(BCOB)=-"Area of triangle" BCO=(P_(0)V_(0))/(2)` `W_(AODA)=+"Area of triangle" AOD=+(P_(0)V_(0))/(2)` `therefore W_("net")=0` |
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