1.

A thermodynamic system undergoes cyclic process `ABCDA` as shown in figure. The work done by the system is

Answer» `W_(BCOB)=-"Area of triangle" BCO=(P_(0)V_(0))/(2)`
`W_(AODA)=+"Area of triangle" AOD=+(P_(0)V_(0))/(2)`
`therefore W_("net")=0`


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