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A thermos bottle containing coffee is vigorouslyshaken. Consider coffee as a system: Has its internal energy changed ?

Answer»

Solution :`DeltaQ=DeltaU+Delta` But `DeltaQ=0,thereforeDeltaU=-DeltaW`, here `DeltaW`is negative because WORK is done on the SYSTEM. Now A [7 is positive, HENCE internal . ENERGY of the system increases


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